Shortstop Stephen Drew rejoins Red Sox on one-year deal

Fitzgerald Cecilio – 4E Sports Reporter

Boston, MA, United States (4E Sports) – The Boston Red Sox signed shortstop Stephen Drew to a one-year deal worth $10.2 million for the remainder of the 2014 season, pending a physical.

The amount was approximately $4 million lower than the $14.1 million qualifying offer from the Red Sox that Drew rejected to pursue a multiyear deal elsewhere that never materialized.

Red Sox manager John Farrell said Drew will undergo a full physical Wednesday. If he passes, the deal will become official.

“We have the ability, provided all things work out, we’ve added a very good player to improve this team,” Farrell said Tuesday. “That’s the thing Ben (Cherington) and ownership have repeatedly shown: When a need exists, they’ll do whatever is capable and whatever is available to improve the team.

“Stephen’s return to us could very well do that. It will add stability to the left side of the infield,” he added.

Farrell estimated that Drew will need roughly 10-12 days and at least 25 at-bats on a minor-league rehabilitation assignment before he is ready to join the major-league club. Once he arrives, Farrell said, rookie Xander Bogaerts will be moved from shortstop to third base.

“We had a chance to sit and talk with Xander,” Farrell said. “He’s aware of everything that’s been talked about and reported, and (we) just wanted to be a little bit ahead of things, as to what it might mean to his position going forward.”

Drew, a .264 career hitter, batted .253 with 13 home runs for the Red Sox last season en route to their World Series championship. Bogaerts has manned shortstop for Boston this year and is batting .269 with a .369 on-base percentage through his first 41 games of the season.

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