Dallas, TX, United States (4E Sports) – The Dallas Cowboys have extended linebacker Sean Lee to a six-year deal for a base value of $42 million plus incentives that could push his pay to $51 million.
The new contract makes Lee the eighth-highest paid inside linebacker, on average, behind David Harris, D’Qwell Jackson, Lawrence Timmons, DeMeco Ryans, Patrick Willis, Paul Posluszny and James Laurinaitis.
He was originally scheduled to make $630,000 this season in what would have been the final year of his rookie contract.
Lee had a team-leading 57 tackles in his first six games before suffering a toe injury in late October against the Carolina Panthers and was placed on the injured reserve list.
He has recorded 125 solo tackles to go along with seven interceptions and 12 pass breakups in 35 career games, including 21 starts. He also returned an interception for a touchdown as a rookie and has forced two fumbles in three seasons.
Lee will now have the responsibility of helping Dallas transition to the 4-3 scheme under new defensive coordinator Monte Kiffin.
The 6’2″, 234-pound Lee was drafted in the second round out of Penn State in 2010.
His agent, Mike McCartney, said that Lee had expressed his desire to be “a Cowboy for life”.